14001224431721 has 2 divisors, whose sum is σ = 14001224431722. Its totient is φ = 14001224431720.

The previous prime is 14001224431681. The next prime is 14001224431723. The reversal of 14001224431721 is 12713442210041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13561807908496 + 439416523225 = 3682636^2 + 662885^2 .

It is a cyclic number.

It is not a de Polignac number, because 14001224431721 - 2⁴² = 9603177920617 is a prime.

Together with 14001224431723, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14001224431723) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7000612215860 + 7000612215861.

It is an arithmetic number, because the mean of its divisors is an integer number (7000612215861).

Almost surely, 2^{14001224431721} is an apocalyptic number.

It is an amenable number.

14001224431721 is a deficient number, since it is larger than the sum of its proper divisors (1).

14001224431721 is an equidigital number, since it uses as much as digits as its factorization.

14001224431721 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10752, while the sum is 32.

Adding to 14001224431721 its reverse (12713442210041), we get a palindrome (26714666641762).

The spelling of 14001224431721 in words is "fourteen trillion, one billion, two hundred twenty-four million, four hundred thirty-one thousand, seven hundred twenty-one".