Base | Representation |
---|---|
bin | 1100101110111111011001… |
… | …0001100100111000010111 |
3 | 1211120112010202010200012011 |
4 | 3023233312101210320113 |
5 | 3313344412114022221 |
6 | 45440100201405051 |
7 | 2643366331130062 |
oct | 313576621447027 |
9 | 54515122120164 |
10 | 14001430220311 |
11 | 4508a78385346 |
12 | 16a16a2799787 |
13 | 7a7438353a61 |
14 | 36595c3a98d9 |
15 | 1943217621e1 |
hex | cbbf6464e17 |
14001430220311 has 2 divisors, whose sum is σ = 14001430220312. Its totient is φ = 14001430220310.
The previous prime is 14001430220279. The next prime is 14001430220333. The reversal of 14001430220311 is 11302203410041.
It is an a-pointer prime, because the next prime (14001430220333) can be obtained adding 14001430220311 to its sum of digits (22).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14001430220311 - 25 = 14001430220279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14001430220381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7000715110155 + 7000715110156.
It is an arithmetic number, because the mean of its divisors is an integer number (7000715110156).
Almost surely, 214001430220311 is an apocalyptic number.
14001430220311 is a deficient number, since it is larger than the sum of its proper divisors (1).
14001430220311 is an equidigital number, since it uses as much as digits as its factorization.
14001430220311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 14001430220311 its reverse (11302203410041), we get a palindrome (25303633630352).
The spelling of 14001430220311 in words is "fourteen trillion, one billion, four hundred thirty million, two hundred twenty thousand, three hundred eleven".
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