Base | Representation |
---|---|
bin | 1100101111000001100100… |
… | …0101101011000001110011 |
3 | 1211120120122110012010002021 |
4 | 3023300121011223001303 |
5 | 3313402111130133243 |
6 | 45440234144332311 |
7 | 2643416652551065 |
oct | 313603105530163 |
9 | 54516573163067 |
10 | 14002014302323 |
11 | 4509248050853 |
12 | 16a1826314097 |
13 | 7a74cc368208 |
14 | 3659b5bab735 |
15 | 194357b886ed |
hex | cbc1916b073 |
14002014302323 has 2 divisors, whose sum is σ = 14002014302324. Its totient is φ = 14002014302322.
The previous prime is 14002014302321. The next prime is 14002014302359. The reversal of 14002014302323 is 32320341020041.
It is a weak prime.
It is an emirp because it is prime and its reverse (32320341020041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14002014302323 - 21 = 14002014302321 is a prime.
Together with 14002014302321, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (14002014302321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7001007151161 + 7001007151162.
It is an arithmetic number, because the mean of its divisors is an integer number (7001007151162).
Almost surely, 214002014302323 is an apocalyptic number.
14002014302323 is a deficient number, since it is larger than the sum of its proper divisors (1).
14002014302323 is an equidigital number, since it uses as much as digits as its factorization.
14002014302323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 14002014302323 its reverse (32320341020041), we get a palindrome (46322355322364).
The spelling of 14002014302323 in words is "fourteen trillion, two billion, fourteen million, three hundred two thousand, three hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.088 sec. • engine limits •