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140023111242317 is a prime number
BaseRepresentation
bin11111110101100110101011…
…110011100101001001001101
3200100210002010101010021221212
4133311212223303211021031
5121323114312434223232
61213445421305104205
741331223141433222
oct3765465363451115
9610702111107855
10140023111242317
11406855169a0706
1213855500788065
13601917984b504
142681224895949
15112c4c8471eb2
hex7f59abce524d

140023111242317 has 2 divisors, whose sum is σ = 140023111242318. Its totient is φ = 140023111242316.

The previous prime is 140023111242271. The next prime is 140023111242383. The reversal of 140023111242317 is 713242111320041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108088168730116 + 31934942512201 = 10396546^2 + 5651101^2 .

It is an emirp because it is prime and its reverse (713242111320041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140023111242317 - 212 = 140023111238221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140023111242017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70011555621158 + 70011555621159.

It is an arithmetic number, because the mean of its divisors is an integer number (70011555621159).

Almost surely, 2140023111242317 is an apocalyptic number.

It is an amenable number.

140023111242317 is a deficient number, since it is larger than the sum of its proper divisors (1).

140023111242317 is an equidigital number, since it uses as much as digits as its factorization.

140023111242317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8064, while the sum is 32.

Adding to 140023111242317 its reverse (713242111320041), we get a palindrome (853265222562358).

The spelling of 140023111242317 in words is "one hundred forty trillion, twenty-three billion, one hundred eleven million, two hundred forty-two thousand, three hundred seventeen".