Base | Representation |
---|---|
bin | 10100011000001001000… |
… | …000000010101011011101 |
3 | 11221212110000221220222101 |
4 | 110120021000002223131 |
5 | 140420313422010123 |
6 | 2551143234245101 |
7 | 203111665352161 |
oct | 24301100025335 |
9 | 4855400856871 |
10 | 1400310344413 |
11 | 49a960757682 |
12 | 1a7481126791 |
13 | a2082cb7216 |
14 | 4babd912ca1 |
15 | 2665a513aad |
hex | 14609002add |
1400310344413 has 2 divisors, whose sum is σ = 1400310344414. Its totient is φ = 1400310344412.
The previous prime is 1400310344387. The next prime is 1400310344437. The reversal of 1400310344413 is 3144430130041.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 755433890649 + 644876453764 = 869157^2 + 803042^2 .
It is a cyclic number.
It is not a de Polignac number, because 1400310344413 - 225 = 1400276789981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1400310344443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700155172206 + 700155172207.
It is an arithmetic number, because the mean of its divisors is an integer number (700155172207).
Almost surely, 21400310344413 is an apocalyptic number.
It is an amenable number.
1400310344413 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400310344413 is an equidigital number, since it uses as much as digits as its factorization.
1400310344413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 1400310344413 its reverse (3144430130041), we get a palindrome (4544740474454).
The spelling of 1400310344413 in words is "one trillion, four hundred billion, three hundred ten million, three hundred forty-four thousand, four hundred thirteen".
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