14003214012433 has 2 divisors, whose sum is σ = 14003214012434. Its totient is φ = 14003214012432.

The previous prime is 14003214012377. The next prime is 14003214012461. The reversal of 14003214012433 is 33421041230041.

It is a happy number.

It is an a-pointer prime, because the next prime (14003214012461) can be obtained adding 14003214012433 to its sum of digits (28).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13453989249024 + 549224763409 = 3667968^2 + 741097^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14003214012433 is a prime.

It is not a weakly prime, because it can be changed into another prime (14003214018433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7001607006216 + 7001607006217.

It is an arithmetic number, because the mean of its divisors is an integer number (7001607006217).

Almost surely, 2^{14003214012433} is an apocalyptic number.

It is an amenable number.

14003214012433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14003214012433 is an equidigital number, since it uses as much as digits as its factorization.

14003214012433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 14003214012433 its reverse (33421041230041), we get a palindrome (47424255242474).

The spelling of 14003214012433 in words is "fourteen trillion, three billion, two hundred fourteen million, twelve thousand, four hundred thirty-three".