Base | Representation |
---|---|
bin | 11010000101010101… |
… | …11011110111111101 |
3 | 1100010220222010210121 |
4 | 31002222323313331 |
5 | 212134341002222 |
6 | 10233314334541 |
7 | 1004006250601 |
oct | 150252736775 |
9 | 40126863717 |
10 | 14003453437 |
11 | 5a36647916 |
12 | 286988a451 |
13 | 142224aa2c |
14 | 96bb35501 |
15 | 56e5b65c7 |
hex | 342abbdfd |
14003453437 has 2 divisors, whose sum is σ = 14003453438. Its totient is φ = 14003453436.
The previous prime is 14003453413. The next prime is 14003453501. The reversal of 14003453437 is 73435430041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9988203481 + 4015249956 = 99941^2 + 63366^2 .
It is a cyclic number.
It is not a de Polignac number, because 14003453437 - 231 = 11855969789 is a prime.
It is a super-2 number, since 2×140034534372 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14003453407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7001726718 + 7001726719.
It is an arithmetic number, because the mean of its divisors is an integer number (7001726719).
Almost surely, 214003453437 is an apocalyptic number.
It is an amenable number.
14003453437 is a deficient number, since it is larger than the sum of its proper divisors (1).
14003453437 is an equidigital number, since it uses as much as digits as its factorization.
14003453437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 34.
Adding to 14003453437 its reverse (73435430041), we get a palindrome (87438883478).
The spelling of 14003453437 in words is "fourteen billion, three million, four hundred fifty-three thousand, four hundred thirty-seven".
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