1400413434001 has 2 divisors, whose sum is σ = 1400413434002. Its totient is φ = 1400413434000.

The previous prime is 1400413433999. The next prime is 1400413434011. The reversal of 1400413434001 is 1004343140041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 840520406401 + 559893027600 = 916799^2 + 748260^2 .

It is an emirp because it is prime and its reverse (1004343140041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1400413434001 - 2¹ = 1400413433999 is a prime.

It is a super-2 number, since 2×1400413434001² (a number of 25 digits) contains 22 as substring.

Together with 1400413433999, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1400413434011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700206717000 + 700206717001.

It is an arithmetic number, because the mean of its divisors is an integer number (700206717001).

Almost surely, 2^{1400413434001} is an apocalyptic number.

It is an amenable number.

1400413434001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1400413434001 is an equidigital number, since it uses as much as digits as its factorization.

1400413434001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1400413434001 its reverse (1004343140041), we get a palindrome (2404756574042).

The spelling of 1400413434001 in words is "one trillion, four hundred billion, four hundred thirteen million, four hundred thirty-four thousand, one".