14004331332120 has 192 divisors, whose sum is σ = 45615055262400. Its totient is φ = 3726211507200.

The previous prime is 14004331332113. The next prime is 14004331332139. The reversal of 14004331332120 is 2123313340041.

It is a happy number.

14004331332120 is a `hidden beast` number, since 1 + 4 + 0 + 0 + 4 + 3 + 313 + 321 + 20 = 666.

It is a super-2 number, since 2×14004331332120² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 328803786 + ... + 328846374.

It is an arithmetic number, because the mean of its divisors is an integer number (237578412825).

Almost surely, 2^{14004331332120} is an apocalyptic number.

14004331332120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14004331332120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22807527631200).

14004331332120 is an abundant number, since it is smaller than the sum of its proper divisors (31610723930280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14004331332120 is a wasteful number, since it uses less digits than its factorization.

14004331332120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44610 (or 44603 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 14004331332120 its reverse (2123313340041), we get a palindrome (16127644672161).

The spelling of 14004331332120 in words is "fourteen trillion, four billion, three hundred thirty-one million, three hundred thirty-two thousand, one hundred twenty".