1401025511 has 2 divisors, whose sum is σ = 1401025512. Its totient is φ = 1401025510.

The previous prime is 1401025489. The next prime is 1401025513. The reversal of 1401025511 is 1155201041.

It is a strong prime.

It is an emirp because it is prime and its reverse (1155201041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1401025511 - 2¹⁰ = 1401024487 is a prime.

It is a super-2 number, since 2×1401025511² = 3925744964945622242, which contains 22 as substring.

Together with 1401025513, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1401025513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700512755 + 700512756.

It is an arithmetic number, because the mean of its divisors is an integer number (700512756).

Almost surely, 2^1401025511 is an apocalyptic number.

1401025511 is a deficient number, since it is larger than the sum of its proper divisors (1).

1401025511 is an equidigital number, since it uses as much as digits as its factorization.

1401025511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 200, while the sum is 20.

The square root of 1401025511 is about 37430.2753262650. The cubic root of 1401025511 is about 1118.9620248937.

Adding to 1401025511 its reverse (1155201041), we get a palindrome (2556226552).

The spelling of 1401025511 in words is "one billion, four hundred one million, twenty-five thousand, five hundred eleven".