140103023412301 has 2 divisors, whose sum is σ = 140103023412302. Its totient is φ = 140103023412300.

The previous prime is 140103023412281. The next prime is 140103023412311. The reversal of 140103023412301 is 103214320301041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115647763221225 + 24455260191076 = 10753965^2 + 4945226^2 .

It is a cyclic number.

It is not a de Polignac number, because 140103023412301 - 2¹⁹ = 140103022888013 is a prime.

It is a super-3 number, since 3×140103023412301³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140103023412311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70051511706150 + 70051511706151.

It is an arithmetic number, because the mean of its divisors is an integer number (70051511706151).

Almost surely, 2^{140103023412301} is an apocalyptic number.

It is an amenable number.

140103023412301 is a deficient number, since it is larger than the sum of its proper divisors (1).

140103023412301 is an equidigital number, since it uses as much as digits as its factorization.

140103023412301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 140103023412301 its reverse (103214320301041), we get a palindrome (243317343713342).

The spelling of 140103023412301 in words is "one hundred forty trillion, one hundred three billion, twenty-three million, four hundred twelve thousand, three hundred one".