140103048031 has 2 divisors, whose sum is σ = 140103048032. Its totient is φ = 140103048030.

The previous prime is 140103048013. The next prime is 140103048091. The reversal of 140103048031 is 130840301041.

Together with previous prime (140103048013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 140103048031 - 2⁵ = 140103047999 is a prime.

It is a super-2 number, since 2×140103048031² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140103047987 and 140103048005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140103048091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70051524015 + 70051524016.

It is an arithmetic number, because the mean of its divisors is an integer number (70051524016).

Almost surely, 2^140103048031 is an apocalyptic number.

140103048031 is a deficient number, since it is larger than the sum of its proper divisors (1).

140103048031 is an equidigital number, since it uses as much as digits as its factorization.

140103048031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 140103048031 its reverse (130840301041), we get a palindrome (270943349072).

The spelling of 140103048031 in words is "one hundred forty billion, one hundred three million, forty-eight thousand, thirty-one".