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14010545111 is a prime number
BaseRepresentation
bin11010000110001011…
…11111001111010111
31100011102022102202012
431003011333033113
5212143144420421
610234130334435
71004123445203
oct150305771727
940142272665
1014010545111
115a3a650a02
12287012a41b
1314238618a4
1496ca5db03
1557001795b
hex34317f3d7

14010545111 has 2 divisors, whose sum is σ = 14010545112. Its totient is φ = 14010545110.

The previous prime is 14010545093. The next prime is 14010545113. The reversal of 14010545111 is 11154501041.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14010545111 is a prime.

Together with 14010545113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14010545113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005272555 + 7005272556.

It is an arithmetic number, because the mean of its divisors is an integer number (7005272556).

Almost surely, 214010545111 is an apocalyptic number.

14010545111 is a deficient number, since it is larger than the sum of its proper divisors (1).

14010545111 is an equidigital number, since it uses as much as digits as its factorization.

14010545111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 400, while the sum is 23.

The spelling of 14010545111 in words is "fourteen billion, ten million, five hundred forty-five thousand, one hundred eleven".