Base | Representation |
---|---|
bin | 11010000110001011… |
… | …11111001111010111 |
3 | 1100011102022102202012 |
4 | 31003011333033113 |
5 | 212143144420421 |
6 | 10234130334435 |
7 | 1004123445203 |
oct | 150305771727 |
9 | 40142272665 |
10 | 14010545111 |
11 | 5a3a650a02 |
12 | 287012a41b |
13 | 14238618a4 |
14 | 96ca5db03 |
15 | 57001795b |
hex | 34317f3d7 |
14010545111 has 2 divisors, whose sum is σ = 14010545112. Its totient is φ = 14010545110.
The previous prime is 14010545093. The next prime is 14010545113. The reversal of 14010545111 is 11154501041.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14010545111 is a prime.
Together with 14010545113, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14010545113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005272555 + 7005272556.
It is an arithmetic number, because the mean of its divisors is an integer number (7005272556).
Almost surely, 214010545111 is an apocalyptic number.
14010545111 is a deficient number, since it is larger than the sum of its proper divisors (1).
14010545111 is an equidigital number, since it uses as much as digits as its factorization.
14010545111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 400, while the sum is 23.
The spelling of 14010545111 in words is "fourteen billion, ten million, five hundred forty-five thousand, one hundred eleven".
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