Base | Representation |
---|---|
bin | 11010000110001111… |
… | …11011100110011101 |
3 | 1100011110021022111012 |
4 | 31003013323212131 |
5 | 212143312220433 |
6 | 10234145305005 |
7 | 1004130666242 |
oct | 150307734635 |
9 | 40143238435 |
10 | 14011054493 |
11 | 5a3a969687 |
12 | 2870335165 |
13 | 14239ac6b7 |
14 | 96cb535c9 |
15 | 5700b8848 |
hex | 3431fb99d |
14011054493 has 2 divisors, whose sum is σ = 14011054494. Its totient is φ = 14011054492.
The previous prime is 14011054483. The next prime is 14011054553. The reversal of 14011054493 is 39445011041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13187766244 + 823288249 = 114838^2 + 28693^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14011054493 is a prime.
It is a super-3 number, since 3×140110544933 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14011054483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005527246 + 7005527247.
It is an arithmetic number, because the mean of its divisors is an integer number (7005527247).
Almost surely, 214011054493 is an apocalyptic number.
It is an amenable number.
14011054493 is a deficient number, since it is larger than the sum of its proper divisors (1).
14011054493 is an equidigital number, since it uses as much as digits as its factorization.
14011054493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 32.
The spelling of 14011054493 in words is "fourteen billion, eleven million, fifty-four thousand, four hundred ninety-three".
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