1401110009993 has 2 divisors, whose sum is σ = 1401110009994. Its totient is φ = 1401110009992.

The previous prime is 1401110009963. The next prime is 1401110010031. The reversal of 1401110009993 is 3999000111041.

It is an a-pointer prime, because the next prime (1401110010031) can be obtained adding 1401110009993 to its sum of digits (38).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1246241787904 + 154868222089 = 1116352^2 + 393533^2 .

It is a cyclic number.

It is not a de Polignac number, because 1401110009993 - 2¹⁴ = 1401109993609 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1401110009953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700555004996 + 700555004997.

It is an arithmetic number, because the mean of its divisors is an integer number (700555004997).

Almost surely, 2^{1401110009993} is an apocalyptic number.

It is an amenable number.

1401110009993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1401110009993 is an equidigital number, since it uses as much as digits as its factorization.

1401110009993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8748, while the sum is 38.

The spelling of 1401110009993 in words is "one trillion, four hundred one billion, one hundred ten million, nine thousand, nine hundred ninety-three".