Base | Representation |
---|---|
bin | 11010000110010000… |
… | …01110111001101111 |
3 | 1100011110102022221021 |
4 | 31003020032321233 |
5 | 212143322233201 |
6 | 10234151115011 |
7 | 1004131445602 |
oct | 150310167157 |
9 | 40143368837 |
10 | 14011133551 |
11 | 5a3aa13018 |
12 | 2870372a67 |
13 | 1423a0968c |
14 | 96cb74339 |
15 | 5700d1ea1 |
hex | 34320ee6f |
14011133551 has 2 divisors, whose sum is σ = 14011133552. Its totient is φ = 14011133550.
The previous prime is 14011133533. The next prime is 14011133561. The reversal of 14011133551 is 15533111041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14011133551 - 217 = 14011002479 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14011133561) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005566775 + 7005566776.
It is an arithmetic number, because the mean of its divisors is an integer number (7005566776).
Almost surely, 214011133551 is an apocalyptic number.
14011133551 is a deficient number, since it is larger than the sum of its proper divisors (1).
14011133551 is an equidigital number, since it uses as much as digits as its factorization.
14011133551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 900, while the sum is 25.
Adding to 14011133551 its reverse (15533111041), we get a palindrome (29544244592).
The spelling of 14011133551 in words is "fourteen billion, eleven million, one hundred thirty-three thousand, five hundred fifty-one".
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