140111403461 has 2 divisors, whose sum is σ = 140111403462. Its totient is φ = 140111403460.

The previous prime is 140111403373. The next prime is 140111403463. The reversal of 140111403461 is 164304111041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130172310436 + 9939093025 = 360794^2 + 99695^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140111403461 is a prime.

It is a super-2 number, since 2×140111403461² (a number of 23 digits) contains 22 as substring.

Together with 140111403463, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 140111403461.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140111403463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70055701730 + 70055701731.

It is an arithmetic number, because the mean of its divisors is an integer number (70055701731).

Almost surely, 2^140111403461 is an apocalyptic number.

It is an amenable number.

140111403461 is a deficient number, since it is larger than the sum of its proper divisors (1).

140111403461 is an equidigital number, since it uses as much as digits as its factorization.

140111403461 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 26.

The spelling of 140111403461 in words is "one hundred forty billion, one hundred eleven million, four hundred three thousand, four hundred sixty-one".