14011230000401 has 2 divisors, whose sum is σ = 14011230000402. Its totient is φ = 14011230000400.

The previous prime is 14011230000367. The next prime is 14011230000437. The reversal of 14011230000401 is 10400003211041.

It is a happy number.

14011230000401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13757088993025 + 254141007376 = 3709055^2 + 504124^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14011230000401 is a prime.

It is a super-4 number, since 4×14011230000401⁴ (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 14011230000401.

It is not a weakly prime, because it can be changed into another prime (14011230000491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005615000200 + 7005615000201.

It is an arithmetic number, because the mean of its divisors is an integer number (7005615000201).

Almost surely, 2^{14011230000401} is an apocalyptic number.

It is an amenable number.

14011230000401 is a deficient number, since it is larger than the sum of its proper divisors (1).

14011230000401 is an equidigital number, since it uses as much as digits as its factorization.

14011230000401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 14011230000401 its reverse (10400003211041), we get a palindrome (24411233211442).

The spelling of 14011230000401 in words is "fourteen trillion, eleven billion, two hundred thirty million, four hundred one", and thus it is an aban number.