Base | Representation |
---|---|
bin | 10100011000111001011… |
… | …101101101111111000111 |
3 | 11221221112200220222012002 |
4 | 110120321131231333013 |
5 | 140424000044232333 |
6 | 2551400041415515 |
7 | 203141100440120 |
oct | 24307135557707 |
9 | 4857480828162 |
10 | 1401123430343 |
11 | 4a023871611a |
12 | 1a766949a59b |
13 | a218259c460 |
14 | 4bb598c7047 |
15 | 266a6ac30e8 |
hex | 1463976dfc7 |
1401123430343 has 32 divisors (see below), whose sum is σ = 1753019382912. Its totient is φ = 1090227340800.
The previous prime is 1401123430337. The next prime is 1401123430351. The reversal of 1401123430343 is 3430343211041.
It is a happy number.
It is not a de Polignac number, because 1401123430343 - 24 = 1401123430327 is a prime.
It is a super-2 number, since 2×14011234303432 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1401123430043) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 40688273 + ... + 40722693.
It is an arithmetic number, because the mean of its divisors is an integer number (54781855716).
Almost surely, 21401123430343 is an apocalyptic number.
1401123430343 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1401123430343 is a deficient number, since it is larger than the sum of its proper divisors (351895952569).
1401123430343 is a wasteful number, since it uses less digits than its factorization.
1401123430343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 41835.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 1401123430343 its reverse (3430343211041), we get a palindrome (4831466641384).
The spelling of 1401123430343 in words is "one trillion, four hundred one billion, one hundred twenty-three million, four hundred thirty thousand, three hundred forty-three".
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