Base | Representation |
---|---|
bin | 1100101111100011111100… |
… | …0011100111011110101101 |
3 | 1211121110110111021201111121 |
4 | 3023320333003213132231 |
5 | 3314030010223413201 |
6 | 45444401513420541 |
7 | 2644164422300425 |
oct | 313707703473655 |
9 | 54543414251447 |
10 | 14011241232301 |
11 | 4512152448915 |
12 | 16a358040a751 |
13 | 7a833cb412b1 |
14 | 36620d3b5485 |
15 | 1946e7c3d9a1 |
hex | cbe3f0e77ad |
14011241232301 has 2 divisors, whose sum is σ = 14011241232302. Its totient is φ = 14011241232300.
The previous prime is 14011241232283. The next prime is 14011241232337. The reversal of 14011241232301 is 10323214211041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12743286411076 + 1267954821225 = 3569774^2 + 1126035^2 .
It is a cyclic number.
It is not a de Polignac number, because 14011241232301 - 223 = 14011232843693 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14011241232341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005620616150 + 7005620616151.
It is an arithmetic number, because the mean of its divisors is an integer number (7005620616151).
Almost surely, 214011241232301 is an apocalyptic number.
It is an amenable number.
14011241232301 is a deficient number, since it is larger than the sum of its proper divisors (1).
14011241232301 is an equidigital number, since it uses as much as digits as its factorization.
14011241232301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 14011241232301 its reverse (10323214211041), we get a palindrome (24334455443342).
The spelling of 14011241232301 in words is "fourteen trillion, eleven billion, two hundred forty-one million, two hundred thirty-two thousand, three hundred one".
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