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1401131144440 = 23535028278611
BaseRepresentation
bin10100011000111001111…
…011001001010011111000
311221221120020102212221101
4110120321323021103320
5140424004033110230
62551400515021144
7203141223136156
oct24307173112370
94857506385841
101401131144440
114a0242004905
121a766bb9a7b4
13a2184070701
144bb5a9343d6
15266a75e8aca
hex14639ec94f8

1401131144440 has 16 divisors (see below), whose sum is σ = 3152545075080. Its totient is φ = 560452457760.

The previous prime is 1401131144429. The next prime is 1401131144471. The reversal of 1401131144440 is 444411311041.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 1401131144399 and 1401131144408.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17514139266 + ... + 17514139345.

Almost surely, 21401131144440 is an apocalyptic number.

1401131144440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1401131144440 is an abundant number, since it is smaller than the sum of its proper divisors (1751413930640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1401131144440 is a wasteful number, since it uses less digits than its factorization.

1401131144440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35028278622 (or 35028278618 counting only the distinct ones).

The product of its (nonzero) digits is 3072, while the sum is 28.

Adding to 1401131144440 its reverse (444411311041), we get a palindrome (1845542455481).

The spelling of 1401131144440 in words is "one trillion, four hundred one billion, one hundred thirty-one million, one hundred forty-four thousand, four hundred forty".

Divisors: 1 2 4 5 8 10 20 40 35028278611 70056557222 140113114444 175141393055 280226228888 350282786110 700565572220 1401131144440