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1401133451 is a prime number
BaseRepresentation
bin101001110000011…
…1001100110001011
310121122110221202112
41103200321212023
510332142232301
6351011052535
746502303114
oct12340714613
93548427675
101401133451
116599a3333
123312a114b
13194387663
14d412920b
158301a9bb
hex5383998b

1401133451 has 2 divisors, whose sum is σ = 1401133452. Its totient is φ = 1401133450.

The previous prime is 1401133423. The next prime is 1401133453. The reversal of 1401133451 is 1543311041.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1401133451 is a prime.

It is a super-2 number, since 2×14011334512 = 3926349895022338802, which contains 22 as substring.

Together with 1401133453, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1401133453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700566725 + 700566726.

It is an arithmetic number, because the mean of its divisors is an integer number (700566726).

Almost surely, 21401133451 is an apocalyptic number.

1401133451 is a deficient number, since it is larger than the sum of its proper divisors (1).

1401133451 is an equidigital number, since it uses as much as digits as its factorization.

1401133451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 23.

The square root of 1401133451 is about 37431.7171794188. The cubic root of 1401133451 is about 1118.9907604303.

Adding to 1401133451 its reverse (1543311041), we get a palindrome (2944444492).

The spelling of 1401133451 in words is "one billion, four hundred one million, one hundred thirty-three thousand, four hundred fifty-one".