Base | Representation |
---|---|
bin | 1100101111100110110010… |
… | …0010100010000101110100 |
3 | 1211121112102200011011020220 |
4 | 3023321230202202011310 |
5 | 3314033041100431122 |
6 | 45445005333054340 |
7 | 2644222346332032 |
oct | 313715442420564 |
9 | 54545380134226 |
10 | 14012004311412 |
11 | 4512504161508 |
12 | 16a3753a873b0 |
13 | 7a8431c67cb3 |
14 | 36628288d552 |
15 | 19473ec2125c |
hex | cbe6c8a2174 |
14012004311412 has 24 divisors (see below), whose sum is σ = 32704587300000. Its totient is φ = 4669252307616.
The previous prime is 14012004311287. The next prime is 14012004311419. The reversal of 14012004311412 is 21411340021041.
It is a happy number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14012004311419) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 176933287 + ... + 177012462.
It is an arithmetic number, because the mean of its divisors is an integer number (1362691137500).
Almost surely, 214012004311412 is an apocalyptic number.
14012004311412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
14012004311412 is an abundant number, since it is smaller than the sum of its proper divisors (18692582988588).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14012004311412 is a wasteful number, since it uses less digits than its factorization.
14012004311412 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 353949055 (or 353949053 counting only the distinct ones).
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 14012004311412 its reverse (21411340021041), we get a palindrome (35423344332453).
The spelling of 14012004311412 in words is "fourteen trillion, twelve billion, four million, three hundred eleven thousand, four hundred twelve".
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