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140121532251317 is a prime number
BaseRepresentation
bin11111110111000010010110…
…001001111011110010110101
3200101010111011111121120202102
4133313002112021323302311
5121331222344224020232
61214002535424551445
741341306123262351
oct3767022611736265
9611114144546672
10140121532251317
1140713231aa4471
12138705a9782585
13602553319c946
142685cbdd30461
15112ed38c5c662
hex7f709627bcb5

140121532251317 has 2 divisors, whose sum is σ = 140121532251318. Its totient is φ = 140121532251316.

The previous prime is 140121532251293. The next prime is 140121532251329. The reversal of 140121532251317 is 713152235121041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130588419045841 + 9533113205476 = 11427529^2 + 3087574^2 .

It is a cyclic number.

It is not a de Polignac number, because 140121532251317 - 214 = 140121532234933 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140121532251367) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70060766125658 + 70060766125659.

It is an arithmetic number, because the mean of its divisors is an integer number (70060766125659).

Almost surely, 2140121532251317 is an apocalyptic number.

It is an amenable number.

140121532251317 is a deficient number, since it is larger than the sum of its proper divisors (1).

140121532251317 is an equidigital number, since it uses as much as digits as its factorization.

140121532251317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 50400, while the sum is 38.

Adding to 140121532251317 its reverse (713152235121041), we get a palindrome (853273767372358).

The spelling of 140121532251317 in words is "one hundred forty trillion, one hundred twenty-one billion, five hundred thirty-two million, two hundred fifty-one thousand, three hundred seventeen".