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140121532252381 is a prime number
BaseRepresentation
bin11111110111000010010110…
…001001111100000011011101
3200101010111011111121122012211
4133313002112021330003131
5121331222344224034011
61214002535425000421
741341306123265431
oct3767022611740335
9611114144548184
10140121532252381
1140713231aa5249
12138705a9783111
1360255331a0284
142685cbdd309c1
15112ed38c5cb21
hex7f709627c0dd

140121532252381 has 2 divisors, whose sum is σ = 140121532252382. Its totient is φ = 140121532252380.

The previous prime is 140121532252367. The next prime is 140121532252433. The reversal of 140121532252381 is 183252235121041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102278230092900 + 37843302159481 = 10113270^2 + 6151691^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140121532252381 is a prime.

It is a super-2 number, since 2×1401215322523812 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140121532252301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70060766126190 + 70060766126191.

It is an arithmetic number, because the mean of its divisors is an integer number (70060766126191).

Almost surely, 2140121532252381 is an apocalyptic number.

It is an amenable number.

140121532252381 is a deficient number, since it is larger than the sum of its proper divisors (1).

140121532252381 is an equidigital number, since it uses as much as digits as its factorization.

140121532252381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 115200, while the sum is 40.

The spelling of 140121532252381 in words is "one hundred forty trillion, one hundred twenty-one billion, five hundred thirty-two million, two hundred fifty-two thousand, three hundred eighty-one".