Base | Representation |
---|---|
bin | 11111110111000010010110… |
… | …001001111100000101101011 |
3 | 200101010111011111121122102002 |
4 | 133313002112021330011223 |
5 | 121331222344224040043 |
6 | 1214002535425001215 |
7 | 41341306123266023 |
oct | 3767022611740553 |
9 | 611114144548362 |
10 | 140121532252523 |
11 | 40713231aa5368 |
12 | 138705a978320b |
13 | 60255331a0363 |
14 | 2685cbdd30a83 |
15 | 112ed38c5cbb8 |
hex | 7f709627c16b |
140121532252523 has 2 divisors, whose sum is σ = 140121532252524. Its totient is φ = 140121532252522.
The previous prime is 140121532252519. The next prime is 140121532252529. The reversal of 140121532252523 is 325252235121041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140121532252523 - 22 = 140121532252519 is a prime.
It is not a weakly prime, because it can be changed into another prime (140121532252529) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70060766126261 + 70060766126262.
It is an arithmetic number, because the mean of its divisors is an integer number (70060766126262).
Almost surely, 2140121532252523 is an apocalyptic number.
140121532252523 is a deficient number, since it is larger than the sum of its proper divisors (1).
140121532252523 is an equidigital number, since it uses as much as digits as its factorization.
140121532252523 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 140121532252523 its reverse (325252235121041), we get a palindrome (465373767373564).
The spelling of 140121532252523 in words is "one hundred forty trillion, one hundred twenty-one billion, five hundred thirty-two million, two hundred fifty-two thousand, five hundred twenty-three".
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