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140121532252519 is a prime number
BaseRepresentation
bin11111110111000010010110…
…001001111100000101100111
3200101010111011111121122101221
4133313002112021330011213
5121331222344224040034
61214002535425001211
741341306123266016
oct3767022611740547
9611114144548357
10140121532252519
1140713231aa5364
12138705a9783207
1360255331a035c
142685cbdd30a7d
15112ed38c5cbb4
hex7f709627c167

140121532252519 has 2 divisors, whose sum is σ = 140121532252520. Its totient is φ = 140121532252518.

The previous prime is 140121532252459. The next prime is 140121532252523. The reversal of 140121532252519 is 915252235121041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 140121532252519 - 29 = 140121532252007 is a prime.

It is a super-2 number, since 2×1401215322525192 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140121532252529) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70060766126259 + 70060766126260.

It is an arithmetic number, because the mean of its divisors is an integer number (70060766126260).

Almost surely, 2140121532252519 is an apocalyptic number.

140121532252519 is a deficient number, since it is larger than the sum of its proper divisors (1).

140121532252519 is an equidigital number, since it uses as much as digits as its factorization.

140121532252519 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216000, while the sum is 43.

The spelling of 140121532252519 in words is "one hundred forty trillion, one hundred twenty-one billion, five hundred thirty-two million, two hundred fifty-two thousand, five hundred nineteen".