140122010041021 has 2 divisors, whose sum is σ = 140122010041022. Its totient is φ = 140122010041020.

The previous prime is 140122010040979. The next prime is 140122010041049. The reversal of 140122010041021 is 120140010221041.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 138216820599225 + 1905189441796 = 11756565^2 + 1380286^2 .

It is an emirp because it is prime and its reverse (120140010221041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140122010041021 - 2³⁵ = 140087650302653 is a prime.

It is a super-3 number, since 3×140122010041021³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 140122010041021.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140122010044021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70061005020510 + 70061005020511.

It is an arithmetic number, because the mean of its divisors is an integer number (70061005020511).

Almost surely, 2^{140122010041021} is an apocalyptic number.

It is an amenable number.

140122010041021 is a deficient number, since it is larger than the sum of its proper divisors (1).

140122010041021 is an equidigital number, since it uses as much as digits as its factorization.

140122010041021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 128, while the sum is 19.

Adding to 140122010041021 its reverse (120140010221041), we get a palindrome (260262020262062).

The spelling of 140122010041021 in words is "one hundred forty trillion, one hundred twenty-two billion, ten million, forty-one thousand, twenty-one".