Base | Representation |
---|---|
bin | 11111110111000010111001… |
… | …011000111110001011010111 |
3 | 200101010112200200221211112111 |
4 | 133313002321120332023113 |
5 | 121331230102042131144 |
6 | 1214003114223131451 |
7 | 41341326562026556 |
oct | 3767027130761327 |
9 | 611115620854474 |
10 | 140122123395799 |
11 | 40713505754026 |
12 | 13870733743b87 |
13 | 60255c87b788c |
14 | 2685d3864dd9d |
15 | 112ed70acb534 |
hex | 7f70b963e2d7 |
140122123395799 has 2 divisors, whose sum is σ = 140122123395800. Its totient is φ = 140122123395798.
The previous prime is 140122123395713. The next prime is 140122123395851. The reversal of 140122123395799 is 997593321221041.
It is a strong prime.
It is an emirp because it is prime and its reverse (997593321221041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 140122123395799 - 217 = 140122123264727 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140122123395599) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70061061697899 + 70061061697900.
It is an arithmetic number, because the mean of its divisors is an integer number (70061061697900).
Almost surely, 2140122123395799 is an apocalyptic number.
140122123395799 is a deficient number, since it is larger than the sum of its proper divisors (1).
140122123395799 is an equidigital number, since it uses as much as digits as its factorization.
140122123395799 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7348320, while the sum is 58.
The spelling of 140122123395799 in words is "one hundred forty trillion, one hundred twenty-two billion, one hundred twenty-three million, three hundred ninety-five thousand, seven hundred ninety-nine".
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