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140122123395799 is a prime number
BaseRepresentation
bin11111110111000010111001…
…011000111110001011010111
3200101010112200200221211112111
4133313002321120332023113
5121331230102042131144
61214003114223131451
741341326562026556
oct3767027130761327
9611115620854474
10140122123395799
1140713505754026
1213870733743b87
1360255c87b788c
142685d3864dd9d
15112ed70acb534
hex7f70b963e2d7

140122123395799 has 2 divisors, whose sum is σ = 140122123395800. Its totient is φ = 140122123395798.

The previous prime is 140122123395713. The next prime is 140122123395851. The reversal of 140122123395799 is 997593321221041.

It is a strong prime.

It is an emirp because it is prime and its reverse (997593321221041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140122123395799 - 217 = 140122123264727 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140122123395599) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70061061697899 + 70061061697900.

It is an arithmetic number, because the mean of its divisors is an integer number (70061061697900).

Almost surely, 2140122123395799 is an apocalyptic number.

140122123395799 is a deficient number, since it is larger than the sum of its proper divisors (1).

140122123395799 is an equidigital number, since it uses as much as digits as its factorization.

140122123395799 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7348320, while the sum is 58.

The spelling of 140122123395799 in words is "one hundred forty trillion, one hundred twenty-two billion, one hundred twenty-three million, three hundred ninety-five thousand, seven hundred ninety-nine".