Base | Representation |
---|---|
bin | 1100101111100111101011… |
… | …0101101001001001111111 |
3 | 1211121120001101112212102121 |
4 | 3023321322311221021333 |
5 | 3314034034003431421 |
6 | 45445045222503411 |
7 | 2644231321350601 |
oct | 313717265511177 |
9 | 54546041485377 |
10 | 14012244202111 |
11 | 451261760a991 |
12 | 16a3800294b67 |
13 | 7a846c87b15c |
14 | 3662a6697171 |
15 | 194755d09d41 |
hex | cbe7ad6927f |
14012244202111 has 2 divisors, whose sum is σ = 14012244202112. Its totient is φ = 14012244202110.
The previous prime is 14012244202093. The next prime is 14012244202141. The reversal of 14012244202111 is 11120244221041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14012244202111 - 25 = 14012244202079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14012244202141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006122101055 + 7006122101056.
It is an arithmetic number, because the mean of its divisors is an integer number (7006122101056).
Almost surely, 214012244202111 is an apocalyptic number.
14012244202111 is a deficient number, since it is larger than the sum of its proper divisors (1).
14012244202111 is an equidigital number, since it uses as much as digits as its factorization.
14012244202111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1024, while the sum is 25.
Adding to 14012244202111 its reverse (11120244221041), we get a palindrome (25132488423152).
The spelling of 14012244202111 in words is "fourteen trillion, twelve billion, two hundred forty-four million, two hundred two thousand, one hundred eleven".
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