Base | Representation |
---|---|
bin | 1100101111100111111011… |
… | …0010001010101111010001 |
3 | 1211121120020000010001210112 |
4 | 3023321332302022233101 |
5 | 3314034202430244303 |
6 | 45445055545411105 |
7 | 2644233054130325 |
oct | 313717662125721 |
9 | 54546200101715 |
10 | 14012310399953 |
11 | 4512650a14348 |
12 | 16a381a499a95 |
13 | 7a84804b8188 |
14 | 3662b13a9985 |
15 | 19475ba340d8 |
hex | cbe7ec8abd1 |
14012310399953 has 2 divisors, whose sum is σ = 14012310399954. Its totient is φ = 14012310399952.
The previous prime is 14012310399947. The next prime is 14012310400027. The reversal of 14012310399953 is 35999301321041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9749931310144 + 4262379089809 = 3122488^2 + 2064553^2 .
It is a cyclic number.
It is not a de Polignac number, because 14012310399953 - 222 = 14012306205649 is a prime.
It is not a weakly prime, because it can be changed into another prime (14012310399553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006155199976 + 7006155199977.
It is an arithmetic number, because the mean of its divisors is an integer number (7006155199977).
Almost surely, 214012310399953 is an apocalyptic number.
It is an amenable number.
14012310399953 is a deficient number, since it is larger than the sum of its proper divisors (1).
14012310399953 is an equidigital number, since it uses as much as digits as its factorization.
14012310399953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 787320, while the sum is 50.
The spelling of 14012310399953 in words is "fourteen trillion, twelve billion, three hundred ten million, three hundred ninety-nine thousand, nine hundred fifty-three".
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