Base | Representation |
---|---|
bin | 1100101111100111111011… |
… | …0010001010110000011011 |
3 | 1211121120020000010001220021 |
4 | 3023321332302022300123 |
5 | 3314034202430300102 |
6 | 45445055545411311 |
7 | 2644233054130462 |
oct | 313717662126033 |
9 | 54546200101807 |
10 | 14012310400027 |
11 | 4512650a14405 |
12 | 16a381a499b37 |
13 | 7a84804b8214 |
14 | 3662b13a99d9 |
15 | 19475ba34137 |
hex | cbe7ec8ac1b |
14012310400027 has 2 divisors, whose sum is σ = 14012310400028. Its totient is φ = 14012310400026.
The previous prime is 14012310399953. The next prime is 14012310400043. The reversal of 14012310400027 is 72000401321041.
It is a strong prime.
It is an emirp because it is prime and its reverse (72000401321041) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14012310400027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14012310399974 and 14012310400010.
It is not a weakly prime, because it can be changed into another prime (14012310400927) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006155200013 + 7006155200014.
It is an arithmetic number, because the mean of its divisors is an integer number (7006155200014).
Almost surely, 214012310400027 is an apocalyptic number.
14012310400027 is a deficient number, since it is larger than the sum of its proper divisors (1).
14012310400027 is an equidigital number, since it uses as much as digits as its factorization.
14012310400027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 14012310400027 its reverse (72000401321041), we get a palindrome (86012711721068).
The spelling of 14012310400027 in words is "fourteen trillion, twelve billion, three hundred ten million, four hundred thousand, twenty-seven".
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