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14012310400027 is a prime number
BaseRepresentation
bin1100101111100111111011…
…0010001010110000011011
31211121120020000010001220021
43023321332302022300123
53314034202430300102
645445055545411311
72644233054130462
oct313717662126033
954546200101807
1014012310400027
114512650a14405
1216a381a499b37
137a84804b8214
143662b13a99d9
1519475ba34137
hexcbe7ec8ac1b

14012310400027 has 2 divisors, whose sum is σ = 14012310400028. Its totient is φ = 14012310400026.

The previous prime is 14012310399953. The next prime is 14012310400043. The reversal of 14012310400027 is 72000401321041.

It is a strong prime.

It is an emirp because it is prime and its reverse (72000401321041) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14012310400027 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14012310399974 and 14012310400010.

It is not a weakly prime, because it can be changed into another prime (14012310400927) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006155200013 + 7006155200014.

It is an arithmetic number, because the mean of its divisors is an integer number (7006155200014).

Almost surely, 214012310400027 is an apocalyptic number.

14012310400027 is a deficient number, since it is larger than the sum of its proper divisors (1).

14012310400027 is an equidigital number, since it uses as much as digits as its factorization.

14012310400027 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344, while the sum is 25.

Adding to 14012310400027 its reverse (72000401321041), we get a palindrome (86012711721068).

The spelling of 14012310400027 in words is "fourteen trillion, twelve billion, three hundred ten million, four hundred thousand, twenty-seven".