Base | Representation |
---|---|
bin | 11010000110011111… |
… | …00001001000000111 |
3 | 1100011121000100111021 |
4 | 31003033201020013 |
5 | 212144314340312 |
6 | 10234300052011 |
7 | 1004153621242 |
oct | 150317411007 |
9 | 40147010437 |
10 | 14013043207 |
11 | 5a40aa7849 |
12 | 2870b34007 |
13 | 1424227957 |
14 | 96d110259 |
15 | 57035cc07 |
hex | 3433e1207 |
14013043207 has 2 divisors, whose sum is σ = 14013043208. Its totient is φ = 14013043206.
The previous prime is 14013043151. The next prime is 14013043259. The reversal of 14013043207 is 70234031041.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14013043207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14013053207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006521603 + 7006521604.
It is an arithmetic number, because the mean of its divisors is an integer number (7006521604).
Almost surely, 214013043207 is an apocalyptic number.
14013043207 is a deficient number, since it is larger than the sum of its proper divisors (1).
14013043207 is an equidigital number, since it uses as much as digits as its factorization.
14013043207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 25.
Adding to 14013043207 its reverse (70234031041), we get a palindrome (84247074248).
The spelling of 14013043207 in words is "fourteen billion, thirteen million, forty-three thousand, two hundred seven".
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