140132431344251 has 2 divisors, whose sum is σ = 140132431344252. Its totient is φ = 140132431344250.

The previous prime is 140132431344203. The next prime is 140132431344253. The reversal of 140132431344251 is 152443134231041.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140132431344251 is a prime.

Together with 140132431344253, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (140132431344253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70066215672125 + 70066215672126.

It is an arithmetic number, because the mean of its divisors is an integer number (70066215672126).

Almost surely, 2^{140132431344251} is an apocalyptic number.

140132431344251 is a deficient number, since it is larger than the sum of its proper divisors (1).

140132431344251 is an equidigital number, since it uses as much as digits as its factorization.

140132431344251 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 138240, while the sum is 38.

Adding to 140132431344251 its reverse (152443134231041), we get a palindrome (292575565575292).

The spelling of 140132431344251 in words is "one hundred forty trillion, one hundred thirty-two billion, four hundred thirty-one million, three hundred forty-four thousand, two hundred fifty-one".