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140133313141 is a prime number
BaseRepresentation
bin1000001010000010011…
…0001010101001110101
3111101201010112212222221
42002200212022221311
54243443112010031
6144213143122341
713060430336233
oct2024046125165
9441633485887
10140133313141
1154480669298
12231aa4433b1
13102a339a803
146ad5211953
1539a27a6a11
hex20a098aa75

140133313141 has 2 divisors, whose sum is σ = 140133313142. Its totient is φ = 140133313140.

The previous prime is 140133313087. The next prime is 140133313157. The reversal of 140133313141 is 141313331041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91887190641 + 48246122500 = 303129^2 + 219650^2 .

It is a cyclic number.

It is not a de Polignac number, because 140133313141 - 211 = 140133311093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140133314141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70066656570 + 70066656571.

It is an arithmetic number, because the mean of its divisors is an integer number (70066656571).

Almost surely, 2140133313141 is an apocalyptic number.

It is an amenable number.

140133313141 is a deficient number, since it is larger than the sum of its proper divisors (1).

140133313141 is an equidigital number, since it uses as much as digits as its factorization.

140133313141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 140133313141 its reverse (141313331041), we get a palindrome (281446644182).

The spelling of 140133313141 in words is "one hundred forty billion, one hundred thirty-three million, three hundred thirteen thousand, one hundred forty-one".