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14013413144399 is a prime number
BaseRepresentation
bin1100101111101100000010…
…0000110011011101001111
31211121200001212010021210102
43023323000200303131033
53314043432231110044
645445401221201315
72644302304243604
oct313730040633517
954550055107712
1014013413144399
114513067433599
1216a3a8786023b
137a85c7aba096
14366377a206ab
151947c375d24e
hexcbec083374f

14013413144399 has 2 divisors, whose sum is σ = 14013413144400. Its totient is φ = 14013413144398.

The previous prime is 14013413144371. The next prime is 14013413144411. The reversal of 14013413144399 is 99344131431041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14013413144399 - 212 = 14013413140303 is a prime.

It is a super-2 number, since 2×140134131443992 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14013413144329) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006706572199 + 7006706572200.

It is an arithmetic number, because the mean of its divisors is an integer number (7006706572200).

Almost surely, 214013413144399 is an apocalyptic number.

14013413144399 is a deficient number, since it is larger than the sum of its proper divisors (1).

14013413144399 is an equidigital number, since it uses as much as digits as its factorization.

14013413144399 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 559872, while the sum is 47.

The spelling of 14013413144399 in words is "fourteen trillion, thirteen billion, four hundred thirteen million, one hundred forty-four thousand, three hundred ninety-nine".