Base | Representation |
---|---|
bin | 11010000110100011… |
… | …01000001000001101 |
3 | 1100011122001110000111 |
4 | 31003101220020031 |
5 | 212144440034143 |
6 | 10234320000021 |
7 | 1004161413343 |
oct | 150321501015 |
9 | 40148043014 |
10 | 14013596173 |
11 | 5a41345245 |
12 | 2871160011 |
13 | 142438c555 |
14 | 96d215993 |
15 | 57041b99d |
hex | 34346820d |
14013596173 has 2 divisors, whose sum is σ = 14013596174. Its totient is φ = 14013596172.
The previous prime is 14013596171. The next prime is 14013596231. The reversal of 14013596173 is 37169531041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10796664649 + 3216931524 = 103907^2 + 56718^2 .
It is a cyclic number.
It is not a de Polignac number, because 14013596173 - 21 = 14013596171 is a prime.
Together with 14013596171, it forms a pair of twin primes.
It is a zygodrome in base 3.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14013596171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006798086 + 7006798087.
It is an arithmetic number, because the mean of its divisors is an integer number (7006798087).
Almost surely, 214013596173 is an apocalyptic number.
It is an amenable number.
14013596173 is a deficient number, since it is larger than the sum of its proper divisors (1).
14013596173 is an equidigital number, since it uses as much as digits as its factorization.
14013596173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 68040, while the sum is 40.
The spelling of 14013596173 in words is "fourteen billion, thirteen million, five hundred ninety-six thousand, one hundred seventy-three".
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