Base | Representation |
---|---|
bin | 10100011001001010001… |
… | …100000011011101111101 |
3 | 11221222021020220000102121 |
4 | 110121022030003131331 |
5 | 140430033411344123 |
6 | 2551443543322541 |
7 | 203151045363466 |
oct | 24311214033575 |
9 | 4858236800377 |
10 | 1401404012413 |
11 | 4a0372037629 |
12 | 1a7727450451 |
13 | a21c875ba52 |
14 | 4bb84c83d6d |
15 | 266c154875d |
hex | 1464a30377d |
1401404012413 has 2 divisors, whose sum is σ = 1401404012414. Its totient is φ = 1401404012412.
The previous prime is 1401404012387. The next prime is 1401404012471. The reversal of 1401404012413 is 3142104041041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1259303662969 + 142100349444 = 1122187^2 + 376962^2 .
It is a cyclic number.
It is not a de Polignac number, because 1401404012413 - 29 = 1401404011901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1401404012513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700702006206 + 700702006207.
It is an arithmetic number, because the mean of its divisors is an integer number (700702006207).
Almost surely, 21401404012413 is an apocalyptic number.
It is an amenable number.
1401404012413 is a deficient number, since it is larger than the sum of its proper divisors (1).
1401404012413 is an equidigital number, since it uses as much as digits as its factorization.
1401404012413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 1401404012413 its reverse (3142104041041), we get a palindrome (4543508053454).
The spelling of 1401404012413 in words is "one trillion, four hundred one billion, four hundred four million, twelve thousand, four hundred thirteen".
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