14014123117 has 2 divisors, whose sum is σ = 14014123118. Its totient is φ = 14014123116.

The previous prime is 14014123093. The next prime is 14014123129. The reversal of 14014123117 is 71132141041.

14014123117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12136547556 + 1877575561 = 110166^2 + 43331^2 .

It is a cyclic number.

It is not a de Polignac number, because 14014123117 - 2¹⁹ = 14013598829 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14014123091 and 14014123100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14014123187) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7007061558 + 7007061559.

It is an arithmetic number, because the mean of its divisors is an integer number (7007061559).

Almost surely, 2^14014123117 is an apocalyptic number.

It is an amenable number.

14014123117 is a deficient number, since it is larger than the sum of its proper divisors (1).

14014123117 is an equidigital number, since it uses as much as digits as its factorization.

14014123117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 672, while the sum is 25.

Adding to 14014123117 its reverse (71132141041), we get a palindrome (85146264158).

The spelling of 14014123117 in words is "fourteen billion, fourteen million, one hundred twenty-three thousand, one hundred seventeen".