140142411133 has 2 divisors, whose sum is σ = 140142411134. Its totient is φ = 140142411132.

The previous prime is 140142411023. The next prime is 140142411139. The reversal of 140142411133 is 331114241041.

140142411133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 140131932964 + 10478169 = 374342^2 + 3237^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140142411133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140142411098 and 140142411107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140142411139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70071205566 + 70071205567.

It is an arithmetic number, because the mean of its divisors is an integer number (70071205567).

Almost surely, 2^140142411133 is an apocalyptic number.

It is an amenable number.

140142411133 is a deficient number, since it is larger than the sum of its proper divisors (1).

140142411133 is an equidigital number, since it uses as much as digits as its factorization.

140142411133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 140142411133 its reverse (331114241041), we get a palindrome (471256652174).

The spelling of 140142411133 in words is "one hundred forty billion, one hundred forty-two million, four hundred eleven thousand, one hundred thirty-three".