14014311341 has 2 divisors, whose sum is σ = 14014311342. Its totient is φ = 14014311340.

The previous prime is 14014311323. The next prime is 14014311343. The reversal of 14014311341 is 14311341041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13802725225 + 211586116 = 117485^2 + 14546^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14014311341 is a prime.

It is a Sophie Germain prime.

Together with 14014311343, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14014311343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7007155670 + 7007155671.

It is an arithmetic number, because the mean of its divisors is an integer number (7007155671).

Almost surely, 2^14014311341 is an apocalyptic number.

It is an amenable number.

14014311341 is a deficient number, since it is larger than the sum of its proper divisors (1).

14014311341 is an equidigital number, since it uses as much as digits as its factorization.

14014311341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 14014311341 its reverse (14311341041), we get a palindrome (28325652382).

The spelling of 14014311341 in words is "fourteen billion, fourteen million, three hundred eleven thousand, three hundred forty-one".