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14014313401147 is a prime number
BaseRepresentation
bin1100101111101111011000…
…1011000000101100111011
31211121202101121010001212221
43023323312023000230323
53314102303212314042
645450030420544511
72644333515302053
oct313736613005473
954552347101787
1014014313401147
114513489620834
1216a4099252137
137a870c473597
14366421406563
151948277dad67
hexcbef62c0b3b

14014313401147 has 2 divisors, whose sum is σ = 14014313401148. Its totient is φ = 14014313401146.

The previous prime is 14014313401069. The next prime is 14014313401181. The reversal of 14014313401147 is 74110431341041.

It is an a-pointer prime, because the next prime (14014313401181) can be obtained adding 14014313401147 to its sum of digits (34).

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14014313401147 is a prime.

It is not a weakly prime, because it can be changed into another prime (14014313501147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7007156700573 + 7007156700574.

It is an arithmetic number, because the mean of its divisors is an integer number (7007156700574).

Almost surely, 214014313401147 is an apocalyptic number.

14014313401147 is a deficient number, since it is larger than the sum of its proper divisors (1).

14014313401147 is an equidigital number, since it uses as much as digits as its factorization.

14014313401147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 34.

Adding to 14014313401147 its reverse (74110431341041), we get a palindrome (88124744742188).

The spelling of 14014313401147 in words is "fourteen trillion, fourteen billion, three hundred thirteen million, four hundred one thousand, one hundred forty-seven".