1402012111 has 2 divisors, whose sum is σ = 1402012112. Its totient is φ = 1402012110.

The previous prime is 1402012099. The next prime is 1402012123. The reversal of 1402012111 is 1112102041.

It is a balanced prime because it is at equal distance from previous prime (1402012099) and next prime (1402012123).

It is a cyclic number.

It is not a de Polignac number, because 1402012111 - 2¹¹ = 1402010063 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1402012091 and 1402012100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1402012141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701006055 + 701006056.

It is an arithmetic number, because the mean of its divisors is an integer number (701006056).

Almost surely, 2^1402012111 is an apocalyptic number.

1402012111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1402012111 is an equidigital number, since it uses as much as digits as its factorization.

1402012111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 13.

The square root of 1402012111 is about 37443.4521779176. The cubic root of 1402012111 is about 1119.2246203732.

Adding to 1402012111 its reverse (1112102041), we get a palindrome (2514114152).

The spelling of 1402012111 in words is "one billion, four hundred two million, twelve thousand, one hundred eleven".