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140201311311421 is a prime number
BaseRepresentation
bin11111111000001100101001…
…010110111001011000111101
3200101102010002102222202012021
4133320030221112321120331
5121334024241143431141
61214103332051040141
741350132123144333
oct3770145126713075
9611363072882167
10140201311311421
1140744051216098
1213883b535a0051
13602cc085c8299
142689acb5d5b53
151131e57b376d1
hex7f83295b963d

140201311311421 has 2 divisors, whose sum is σ = 140201311311422. Its totient is φ = 140201311311420.

The previous prime is 140201311311377. The next prime is 140201311311473. The reversal of 140201311311421 is 124113113102041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 138801715839396 + 1399595472025 = 11781414^2 + 1183045^2 .

It is a cyclic number.

It is not a de Polignac number, because 140201311311421 - 217 = 140201311180349 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140201321311421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70100655655710 + 70100655655711.

It is an arithmetic number, because the mean of its divisors is an integer number (70100655655711).

Almost surely, 2140201311311421 is an apocalyptic number.

It is an amenable number.

140201311311421 is a deficient number, since it is larger than the sum of its proper divisors (1).

140201311311421 is an equidigital number, since it uses as much as digits as its factorization.

140201311311421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 140201311311421 its reverse (124113113102041), we get a palindrome (264314424413462).

The spelling of 140201311311421 in words is "one hundred forty trillion, two hundred one billion, three hundred eleven million, three hundred eleven thousand, four hundred twenty-one".