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14020134253 is a prime number
BaseRepresentation
bin11010000111010101…
…00100010101101101
31100012002100121120121
431003222210111231
5212203123244003
610235112044541
71004301113656
oct150352442555
940162317517
1014020134253
115a45000414
122873393751
13142583b438
1497003852d
15570cadcbd
hex343aa456d

14020134253 has 2 divisors, whose sum is σ = 14020134254. Its totient is φ = 14020134252.

The previous prime is 14020134229. The next prime is 14020134259. The reversal of 14020134253 is 35243102041.

14020134253 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11422906884 + 2597227369 = 106878^2 + 50963^2 .

It is a cyclic number.

It is not a de Polignac number, because 14020134253 - 217 = 14020003181 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14020134259) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7010067126 + 7010067127.

It is an arithmetic number, because the mean of its divisors is an integer number (7010067127).

Almost surely, 214020134253 is an apocalyptic number.

It is an amenable number.

14020134253 is a deficient number, since it is larger than the sum of its proper divisors (1).

14020134253 is an equidigital number, since it uses as much as digits as its factorization.

14020134253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 14020134253 its reverse (35243102041), we get a palindrome (49263236294).

The spelling of 14020134253 in words is "fourteen billion, twenty million, one hundred thirty-four thousand, two hundred fifty-three".