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140213100341042 = 21753367212015563
BaseRepresentation
bin11111111000010111101000…
…000010011110011100110010
3200101110020112001010111120222
4133320113220002132130302
5121334222412141403132
61214113001542533042
741351030223223151
oct3770275002363462
9611406461114528
10140213100341042
1140749050881583
12138862a3737182
136031066b34361
14268a4c91b7598
1511323e7ad3412
hex7f85e809e732

140213100341042 has 32 divisors (see below), whose sum is σ = 227511357541632. Its totient is φ = 64561282815744.

The previous prime is 140213100340997. The next prime is 140213100341053. The reversal of 140213100341042 is 240143001312041.

It is a super-3 number, since 3×1402131003410423 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 105346448 + ... + 106669115.

It is an arithmetic number, because the mean of its divisors is an integer number (7109729923176).

Almost surely, 2140213100341042 is an apocalyptic number.

140213100341042 is a deficient number, since it is larger than the sum of its proper divisors (87298257200590).

140213100341042 is a wasteful number, since it uses less digits than its factorization.

140213100341042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 212016002.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 140213100341042 its reverse (240143001312041), we get a palindrome (380356101653083).

The spelling of 140213100341042 in words is "one hundred forty trillion, two hundred thirteen billion, one hundred million, three hundred forty-one thousand, forty-two".

Divisors: 1 2 17 34 53 106 367 734 901 1802 6239 12478 19451 38902 330667 661334 212015563 424031126 3604264571 7208529142 11236824839 22473649678 77809711621 155619423242 191026022263 382052044526 1322765097557 2645530195114 4123914715913 8247829431826 70106550170521 140213100341042