140213112022433 has 4 divisors (see below), whose sum is σ = 140240534893188. Its totient is φ = 140185689151680.

The previous prime is 140213112022387. The next prime is 140213112022469. The reversal of 140213112022433 is 334220211312041.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 74016289105984 + 66196822916449 = 8603272^2 + 8136143^2 .

It is a cyclic number.

It is not a de Polignac number, because 140213112022433 - 2⁶ = 140213112022369 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140213112022396 and 140213112022405.

It is not an unprimeable number, because it can be changed into a prime (140213112025433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13711427708 + ... + 13711437933.

It is an arithmetic number, because the mean of its divisors is an integer number (35060133723297).

Almost surely, 2^{140213112022433} is an apocalyptic number.

It is an amenable number.

140213112022433 is a deficient number, since it is larger than the sum of its proper divisors (27422870755).

140213112022433 is an equidigital number, since it uses as much as digits as its factorization.

140213112022433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27422870754.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 140213112022433 its reverse (334220211312041), we get a palindrome (474433323334474).

The spelling of 140213112022433 in words is "one hundred forty trillion, two hundred thirteen billion, one hundred twelve million, twenty-two thousand, four hundred thirty-three".