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140213112022469 is a prime number
BaseRepresentation
bin11111111000010111101000…
…101111000010010111000101
3200101110020112212002222111102
4133320113220233002113011
5121334222423134204334
61214113003041145445
741351030424424613
oct3770275057022705
9611406485088442
10140213112022469
114074905742aa52
12138862a762b285
136031069394345
14268a4ca9786b3
1511323e8b3e67e
hex7f85e8bc25c5

140213112022469 has 2 divisors, whose sum is σ = 140213112022470. Its totient is φ = 140213112022468.

The previous prime is 140213112022387. The next prime is 140213112022471. The reversal of 140213112022469 is 964220211312041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 136807223317444 + 3405888705025 = 11696462^2 + 1845505^2 .

It is a cyclic number.

It is not a de Polignac number, because 140213112022469 - 224 = 140213095245253 is a prime.

It is a super-2 number, since 2×1402131120224692 (a number of 29 digits) contains 22 as substring.

Together with 140213112022471, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140213112022369) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70106556011234 + 70106556011235.

It is an arithmetic number, because the mean of its divisors is an integer number (70106556011235).

Almost surely, 2140213112022469 is an apocalyptic number.

It is an amenable number.

140213112022469 is a deficient number, since it is larger than the sum of its proper divisors (1).

140213112022469 is an equidigital number, since it uses as much as digits as its factorization.

140213112022469 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 38.

The spelling of 140213112022469 in words is "one hundred forty trillion, two hundred thirteen billion, one hundred twelve million, twenty-two thousand, four hundred sixty-nine".