140213112025433 has 2 divisors, whose sum is σ = 140213112025434. Its totient is φ = 140213112025432.

The previous prime is 140213112025421. The next prime is 140213112025451. The reversal of 140213112025433 is 334520211312041.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 115485048481609 + 24728063543824 = 10746397^2 + 4972732^2 .

It is a cyclic number.

It is not a de Polignac number, because 140213112025433 - 2²⁰ = 140213110976857 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 140213112025433.

It is not a weakly prime, because it can be changed into another prime (140213112025403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70106556012716 + 70106556012717.

It is an arithmetic number, because the mean of its divisors is an integer number (70106556012717).

Almost surely, 2^{140213112025433} is an apocalyptic number.

It is an amenable number.

140213112025433 is a deficient number, since it is larger than the sum of its proper divisors (1).

140213112025433 is an equidigital number, since it uses as much as digits as its factorization.

140213112025433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 140213112025433 its reverse (334520211312041), we get a palindrome (474733323337474).

The spelling of 140213112025433 in words is "one hundred forty trillion, two hundred thirteen billion, one hundred twelve million, twenty-five thousand, four hundred thirty-three".