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140214132021343 is a prime number
BaseRepresentation
bin11111111000011000100101…
…100010000001100001011111
3200101110100011221102021220111
4133320120211202001201133
5121334232020244140333
61214113252155230451
741351064621321352
oct3770304542014137
9611410157367814
10140214132021343
1140749530173226
1213886531148427
13603119c7b4283
14268a586210299
1511324584714cd
hex7f862588185f

140214132021343 has 2 divisors, whose sum is σ = 140214132021344. Its totient is φ = 140214132021342.

The previous prime is 140214132021331. The next prime is 140214132021497. The reversal of 140214132021343 is 343120231412041.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140214132021343 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140214132025343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70107066010671 + 70107066010672.

It is an arithmetic number, because the mean of its divisors is an integer number (70107066010672).

Almost surely, 2140214132021343 is an apocalyptic number.

140214132021343 is a deficient number, since it is larger than the sum of its proper divisors (1).

140214132021343 is an equidigital number, since it uses as much as digits as its factorization.

140214132021343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 140214132021343 its reverse (343120231412041), we get a palindrome (483334363433384).

The spelling of 140214132021343 in words is "one hundred forty trillion, two hundred fourteen billion, one hundred thirty-two million, twenty-one thousand, three hundred forty-three".